0 like 0 dislike
A ball is launched from a platform. The equation for the ball’s height h at time t seconds after launch is h(t)=-4.9t^2+16.17t+71.05 where h is in meters. What is the initial height of the ball before launch?
by

1 Answer

0 like 0 dislike
71.055 [m].

Step-by-step explanation:

1) according to the condition t=0 (initiat height means elapsed time is zero), then

2) h(0)=4.9*0+16.17*0+71.05; ⇔ h(0)=71.05 [m].
by
Welcome to AskTheTask.com, where understudies, educators and math devotees can ask and respond to any number related inquiry. Find support and replies to any numerical statement including variable based math, geometry, calculation, analytics, geometry, divisions, settling articulation, improving on articulations from there, the sky is the limit. Find solutions to numerical problems. Help is consistently 100 percent free!

Questions

No related questions found