0 like 0 dislike
Examine the following graph, where P(x) is the preimage and I(x) is the image after a transformation.

P of X is a cube root function and I of X is the same function translated 4 units to the right.

© 2018 StrongMind. Created using GeoGebra.

Which function correctly describes the transformation?

I(x)=P(x)−4cap i times x is equal to cap p times x minus 4, , ,

I(x)=P(x)+4cap i times x is equal to cap p times x plus 4, , ,

I(x)=P(x+4)cap i times x is equal to cap p times open paren x plus 4 close paren, , ,


1 Answer

0 like 0 dislike
the 4th answer I(x) = P(x-4)

Step-by-step explanation:

the first 2 options are out, because just adding values to the functional result values changes the y value, and the curve is pushed up or down. but not to the side.

just imagine

I(x) = P(x-4) means that the function value of previously at x-4 happens now at x. 4 units "later" (or more to the right).

"x+4" would make the functional value at previously x+4 happen now at x. so, everything would shift to the left (happen "earlier").

therefore, the 4th answer option is correct.
Welcome to AskTheTask.com, where understudies, educators and math devotees can ask and respond to any number related inquiry. Find support and replies to any numerical statement including variable based math, geometry, calculation, analytics, geometry, divisions, settling articulation, improving on articulations from there, the sky is the limit. Find solutions to numerical problems. Help is consistently 100 percent free!


No related questions found