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in Parity of function:
if f(x) odd and g(x)=f(x)+2 Then g(x) is:?
(a) Even
(b) odd
(c) neither odd nor Even ​
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(c) neither odd nor Even

Step-by-step explanation: ​

f(x) odd ⇒ f(-x) = - f(x)

⇒ g(-x) = f(-x) + 2 = - f(x) + 2

Since - f(x) + 2 ≠ - f(x) - 2 and - f(x) + 2 ≠ f(x) + 2

Then g(-x) ≠ - g(x) and g(-x) ≠ g(x)

Then g is neither odd nor even
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