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Imagine that you have a hollow spherical conductor carrying a net charge $$\displaystyle +Q$$ that has inner radius $$\displaystyle R_1$$ and outer radius $$\displaystyle R_2$$. Now imagine again that you threw a point charge, $$\displaystyle +Q/2$$, at the center of the sphere. Find the potential as a function of $$\displaystyle r$$, the distance from the center, for $$\displaystyle 0 ## Please log in or register to answer this question. 0 like 0 dislike Why do you think? Did you answer my question? Thread closed. -Dan by 0 like 0 dislike topsquark said: I know all that. What do you know? Give, or I'm closing the thread. -Dan Click to expand... Why are you upset, Dan? by 0 like 0 dislike george357 said: Just a warming up. \(\displaystyle \Delta V = \int dE$$ Click to expand... I know all that. What do you know? Give, or I'm closing the thread. -Dan
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Just a warming up. $$\displaystyle \Delta V = \int dE$$
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george357 said: Imagine that you have a hollow spherical conductor carrying a net charge $$\displaystyle +Q$$ that has inner radius $$\displaystyle R_1$$ and outer radius $$\displaystyle R_2$$. Now imagine again that you threw a point charge, $$\displaystyle +Q/2$$, at the center of the sphere. Find the potential as a function of $$\displaystyle r$$, the distance from the center, for $$\displaystyle 0 by 0 like 0 dislike CaptainBlack said: Take this to the Physics Help Forum. Click to expand... Believe me or not, once you see the electric field formula, you will say it is a pure calculus. Don't let physics symbols scares you, it is just a fancy way to talk about mathematics. by 0 like 0 dislike george357 said: Imagine that you have a hollow spherical conductor carrying a net charge \(\displaystyle +Q$$ that has inner radius $$\displaystyle R_1$$ and outer radius $$\displaystyle R_2$$. Now imagine again that you threw a point charge, $$\displaystyle +Q/2$$, at the center of the sphere. Find the potential as a function of $$\displaystyle r$$, the distance from the center, for \(\displaystyle 0
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