SupremeCookie said: A lot of the outcomes are missing, what about e.g. (5,0), (5,1),...(4,0),(4,1), ect...? Click to expand... ahhh mouse slip. I did only the 6. CaptainBlack said: You can't throw a "0" on a D6. Click to expand... The zero is problematic. Plato said: Here are all thirty-six of the pairs. Now just count. \(\displaystyle \begin{array}{*{20}{c}} {(1,1)}&{(1,2)}&{(1,3)}&{(1,4)}&{(1,5)}&{(1,6)} \\ {(2,1)}&{(2,2)}&{(2,3)}&{(2,4)}&{(2,5)}&{(2,6)} \\ {(3,1)}&{(3,2)}&{(3,3)}&{(3,4)}&{(3,5)}&{(3,6)} \\ {(4,1)}&{(4,2)}&{(4,3)}&{(4,4)}&{(4,5)}&{(4,6)} \\ {(5,1)}&{(5,2)}&{(5,3)}&{(5,4)}&{(5,5)}&{(5,6)} \\ {(6,1)}&{(6,2)}&{(6,3)}&{(6,4)}&{(6,5)}&{(6,6)} \end{array}\) Click to expand... I have already done the 6. Remove |6-0|, so we have X =,0,1,2,3,4,5. There is a clear pattern what will happen for the rest. 5 4,4 3,3,3 2,2,2,2 1,1,1,1,1 0,0,0,0,0,0