Hi student, let me help you out!

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Part 1.

What is the slope of the line [tex]\mathtt{y=4-2x}[/tex]?

- slope = -2

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Part 2.

What is the slope of the line that is parallel to the line [tex]\mathtt{y=4-2x}[/tex]?

- slope = [tex]\mathtt{-2}[/tex]

[tex]\dag\mathtt{Drawing\:Conclusions}[/tex]

The slopes of parallel lines are identical.

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Part 3. Equation

Now that we've found the slope, we can easily find the equation.

Recall the point that the line contains: (2, -1).

Let's stick in its y-coordinate, -1, instead of y: [tex]\mathtt{-1=-2x+b}[/tex]

Do the exact same thing with x: [tex]\mathtt{-1=-2(2)+b}[/tex].

Upon simplifying, we obtain [tex]\mathtt{-1=-4+b}[/tex].

Now we should add 4 to both sides: [tex]\mathtt{-1+4=b}[/tex].

Upon simplifying, we obtain [tex]\mathtt{3=b}[/tex]

- Incase you're wondering, "b" is the y-intercept.

∴, the equation of the line is [tex]\underline{\boxed{\mathtt{y=-2x+3}}}[/tex].

Hope this helped you out, ask in comments if any queries arise.

Best Regards!

[tex]\star\bigstar\underline{\underline{\overline{\overline{\bold{Reach\:Far.\:Aim\:high.\:Dream\:big.}}}}}\bigstar\star[/tex]

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