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"eight times the difference of a number and three is sixty-four"?

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$$\bold{Let:}$$ $$\star$$

$$\mathsf{s\:be\:the\:number}$$

The little phrase (eight times) tells us to multiply s times 8: $$\mathsf{8s}$$.

The phrase (the difference of) tells us to subtract 3 minus s: $$\mathsf{s-3}$$.

Now, the problem also tells us to multiply 8 times 3-s: $$\mathsf{8(s-3)}$$.

Notice I put parentheses around 3-s. This tells us to multiply 8 times both terms - 3 and -s. $$\star$$

Finally, this expression is 64. All of our hard work results in the following equation: ✨ $$\bigstar\underline{\boxed{\mathrm{8(s-3)=64}}}$$ $$\star$$

Hope this helped you out, ask in comments if any queries arise.

Best Regards! $$\star$$

$$\star\bigstar\underline{\underline{\overline{\overline{\bold{Reach\:far.\:Aim\:high.\:Dream\:big.}}}}}\bigstar\star$$
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the number would be 11

Step-by-step explanation:

8 · x - 3 = 64

________ _ (divide both sides by 8)

8 8

x - 3 = 8

+ 3 + 3

x = 11

(check:

11 - 3 = 8

8 x 8 = 64 )
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