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"eight times the difference of a number and three is sixty-four"?
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2 Answers

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Hi student, let me help you out!

................................................................................................................................

[tex]\bold{Let:}[/tex] [tex]\star[/tex]

[tex]\mathsf{s\:be\:the\:number}[/tex]

The little phrase (eight times) tells us to multiply s times 8: [tex]\mathsf{8s}[/tex].

The phrase (the difference of) tells us to subtract 3 minus s: [tex]\mathsf{s-3}[/tex].

Now, the problem also tells us to multiply 8 times 3-s: [tex]\mathsf{8(s-3)}[/tex].

Notice I put parentheses around 3-s. This tells us to multiply 8 times both terms - 3 and -s. [tex]\star[/tex]

Finally, this expression is 64. All of our hard work results in the following equation: ✨ [tex]\bigstar\underline{\boxed{\mathrm{8(s-3)=64}}}[/tex] [tex]\star[/tex]

Hope this helped you out, ask in comments if any queries arise.

Best Regards! [tex]\star[/tex]

[tex]\star\bigstar\underline{\underline{\overline{\overline{\bold{Reach\:far.\:Aim\:high.\:Dream\:big.}}}}}\bigstar\star[/tex]
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the number would be 11

Step-by-step explanation:

8 · x - 3 = 64

________ _ (divide both sides by 8)

8 8

x - 3 = 8

+ 3 + 3

x = 11

(check:

11 - 3 = 8

8 x 8 = 64 )
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