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Which of the following is an extraneous solution of √4x+41 = x+5?
Ox=-8
Ox=-2
Ox=2
O x=8
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x=-8

Step-by-step explanation:

on squaring both sides

either x-2=0 or x+8=0

either x=2 or x=-8

Putting x=2 in original equation, we get

7=7 hence, it is not an extraneous solution

Putting x=-8 in original equation

i.e. 3=-3

Hence, x=-8 is an extraneous solution (since it doesn't satisfy the original equation)
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