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Given that MATH is a parallelogram, solve for c.
A. 74
B. 84
C. 94
D. 104​
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C. 94

Step-by-step explanation:

Given that,

∠M = ∠T

(Opposite angles of the parallelogram)

- b - 10 = 86°
- b = 86 + 10
- b = 96°

Now, ∠H + ∠T = 180°.

(Adjacent angles of the same size)

- x + b - 10 = 180°
- x + 96 - 10 = 180°
- x + 86 = 180°
- x = 180 - 86
- x = 94°

Now, ∠H = ∠A

(Opposite angles)

- c° = x°
- c = 94°
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