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Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options.

The radius of the circle is 3 units.
The center of the circle lies on the x-axis.
The center of the circle lies on the y-axis.
The standard form of the equation is (x – 1)² + y² = 3.
The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.
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Placing the equation of the circle in standard-form, the correct statements are given as follows:

- The radius of the circle is 3 units.

- The center of the circle lies on the x-axis.

- The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

What is the equation of a circle?

The equation of a circle of center [tex](x_0, y_0)[/tex] and radius r is given by:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

In this problem, the equation is:

x² + y² - 2x - 8 = 0.

In standard-form:

x² - 2x + y² = 8

(x - 1)² + y² = 8 + 1²

(x - 1)² + y² = 9

Center of (1,0), on the x-axis, radius of 3, hence the correct statements are:

- The radius of the circle is 3 units.

- The center of the circle lies on the x-axis.

- The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

More can be learned about the equation of a circle at  
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