0 like 0 dislike
Solve using the quadratic formula. 9q2 + 6q + 1 = 0 Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth. q = or q =

0 like 0 dislike
The solution to the quadratic equation is given as follows: $$q = -\frac{1}{3}$$

A quadratic function is given according to the following rule:

$$y = ax^2 + bx + c$$

The solutions are:

- $$x_1 = \frac{-b + \sqrt{\Delta}}{2a}$$

- $$x_2 = \frac{-b - \sqrt{\Delta}}{2a}$$

In which:

$$\Delta = b^2 - 4ac$$

In this problem, the equation is:

9q² + 6q + 1.

The coefficients are a = 9,b = 6, c = 1, hence:

$$\Delta = 6^2 - 4(9)(1) = 0$$

$$q_1 = \frac{-6 + \sqrt{0}}{2(9)} = -\frac{1}{3}$$

$$q_2 = \frac{-6 - \sqrt{0}}{2(9)} = -\frac{1}{3}$$