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What is the cube root of -729a^9b^6?
-9a^3b^2
-9a^2b^
-8a^3b^2
-8a^2b^3

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$$= 9a^3b^2$$

Step-by-step explanation:

$$\sqrt[3]{-729a^9b^6} =$$

$$= ((-9)^3a^9b^6)^{\frac{1}{3}$$

$$= (-9)^{3 \times \frac{1}{3}} \times a^{9 \times \frac{1}{3}} \times b^{6 \times \frac{1}{3}}$$

$$= (-9)^{1} \times a^{3} \times b^{2}$$

$$= -9a^3b^2$$
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