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If z is a standard normal variable, find the probability that z lies between-2.41 and 0

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0.4920238

Step-by-step explanation:
Given: z is a standard normal variable.
We know that probability of z lies lies between
two values a and b is given by :-
Pla<2Now, the probability that z lies between -2.41
and O is given by :-
P(-2.41 < 2 < 0) = P(=<0) - P(2< -2.41)
P(-2.41 < 2 < 0) = 0.5 - 0.0079762 = 0.4920238
[By using z-table for standard normal distribution]
Hence, the probability that z lies between -2.41
and 0 = 0.4920238
by