0 like 0 dislike
Find another point on the line that passes through the point (4,5) and has a slope of 2. Explain how you obtained your answer.
by

1 Answer

0 like 0 dislike
well, we know its slope and we also know a point on it, so hmmm without further ado, we can get its equation, once we have the equation, we can get any point we like on it pretty much, so

[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{5})\hspace{10em} \stackrel{slope}{m} ~=~ 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \\\\\\ y-5=2x-8\implies y=2x-3[/tex]

well then hmmm to get some other point hmmm let's pick a random "x" hmmm say dunno x = -13, so

[tex]\underline{x=-13}\hspace{5em}y=2(\stackrel{x}{-13})-3\implies y=-26-3\implies \underline{y=-29} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \underset{another~point}{(-13~~,~~-29)}~\hfill[/tex]
by
Welcome to AskTheTask.com, where understudies, educators and math devotees can ask and respond to any number related inquiry. Find support and replies to any numerical statement including variable based math, geometry, calculation, analytics, geometry, divisions, settling articulation, improving on articulations from there, the sky is the limit. Find solutions to numerical problems. Help is consistently 100 percent free!

Questions

No related questions found