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Which equation is y = 6x2 12x – 10 rewritten in vertex form? y = 6(x 1)2 – 11 y = 6(x 1)2 – 10 y = 6(x 1)2 – 4 y = 6(x 1)2 – 16

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The vertex form of the given quadratic equation is:

$$y = 6*(x + 1)^2 - 16$$

How to rewrite the equation in vertex form?

$$y = 6x^2 + 12x -10$$

First, we need to find the vertex. The x-value of the vertex is:

h = -12/2*6 = -1

To get the y-value of the vertex, we need to evaluate the function in h, so we get:

y = 6 - 12 - 10 = -16

Then the vertex is (-1, -16)

This means that the vertex form is:

$$y = 6*(x + 1)^2 - 16$$