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Paul, who is 1.5 yards tall, was standing on the pier at the
beach approach trying to find his sister. he spotted her at the waters edge at an angle depression of 28 degrees. if the pier is 5 yards above the sand, how far down the beach is paul’s sister?
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5+1.5=6.5 yards
90-28=62 degrees

Imagine a right triangle where the
a=6.5
B=?
C=?
We use SOH-CAH-TOA
Tan(62degrees)=(x/6.5)
=12.2 yards
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