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Find the vertex of the parabola.
y = 2x2 + 8x+12

$$\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{2}x^2\stackrel{\stackrel{b}{\downarrow }}{+8}x\stackrel{\stackrel{c}{\downarrow }}{+12} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 8}{2(2)}~~~~ ,~~~~ 12-\cfrac{ (8)^2}{4(2)}\right)\implies \left( -\cfrac{8}{4}~~,~~12-\cfrac{64}{8} \right) \\\\\\ (-2~~,~~12-8)\implies (-2~~,~~4)$$