Perimeter of ΔA'B'C' is 52 cm.
The perimeter of ΔABC is =13 cm
Length of OB = 5 cm
Length of OB' = 15 + 5 = 20 cm
The Dilation factor can be found out b
ΔOCB and ΔOC'B' are similar as BC|| B'C'
From triangles ΔOCB & ΔOC'B' the dilation factor can be found out
by the formula below
[tex]\frac{BC}{B'C'} =\frac{5}{20}[/tex]
B'C'= 4BC
so the dilation factor = 4
hence the new perimeter of the triangle = 13 4 = 52 cm
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