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Find the sum of the geometric series 100+20+…+0.16

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c) 124.96

Step-by-step explanation:

Geometric series: 100 + 20 + ... + 0.16

First we need to find which term 0.16 is.

General form of a geometric sequence: [tex]a_n=ar^{n-1}[/tex]

(where a is the first term and r is the common ratio)

To find the common ratio r, divide one term by the previous term:

[tex]\implies r=\dfrac{a_2}{a_1}=\dfrac{20}{100}=0.2[/tex]

Therefore, [tex]a_n=100(0.2)^{n-1}[/tex]

Substitute [tex]a_n=0.16[/tex] into the equation and solve for n:

[tex]\implies 100(0.2)^{n-1}=0.16[/tex]

[tex]\implies (0.2)^{n-1}=0.0016[/tex]

[tex]\implies \ln(0.2)^{n-1}=\ln0.0016[/tex]

[tex]\implies (n-1)\ln(0.2)=\ln0.0016[/tex]

[tex]\implies n-1=\dfrac{\ln0.0016}{\ln(0.2)}[/tex]

[tex]\implies n=\dfrac{\ln0.0016}{\ln(0.2)}+1[/tex]

[tex]\implies n=5[/tex]

Therefore, we need to find the sum of the first 5 terms.

Sum of the first n terms of a geometric series:


Therefore, sum of the first 5 terms:

[tex]\implies S_5=\dfrac{100(1-0.2^5)}{1-0.2}[/tex]

[tex]\implies S_5=124.96[/tex]
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