The following that could be used to calculate the total volume of grains that can be stored in the silo is π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

To answer the question, we need to know what volume is.

What is volume?

This is the capacity of a material or container.

Since the silo is made of a cylindrical and a conical part, we need to find the volume of both parts.

Volume of cylindrical part.

So, the volume of the cylindrical part V = πr²h where

- r = radius of cylidrical part = 4 ft/2 = 2 ft and

- h = length of cylindrical part = 8 ft.

So, V = πr²h

V = π(2 ft)²8 ft

Volume of the conical part

The volume of the conical part is given by V' = 1/3πr²h where

- r = radius of cone = 2ft and

- h = height of cone.

Since the entire length of silo is 9.5 ft and length of cylindrical part is 8 ft, then the height of cone is h' = 9.5 ft - 8 ft

So, V' = 1/3πr²h'

V' = 1/3π(2 ft)²(9.5 ft - 8ft)

Total volume of grains in silo

The total volume of grains equals the total volume of the silo V" = V + V'

V" = π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

So, the following that could be used to calculate the total volume of grains that can be stored in the silo is π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

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